Section A — Multiple Choice Questions
Choose the single best answer | Each question carries 1 mark
Q 1
MCQ
A matrix of order m × n has 18 elements. Which of the following is a possible order?
✅ Solution
For an m × n matrix, number of elements = mn = 18.
Factor pairs of 18: (1,18), (2,9), (3,6), (6,3), (9,2), (18,1).
Both 3×6 and 2×9 are valid.
Answer: (D) Both B and C
Factor pairs of 18: (1,18), (2,9), (3,6), (6,3), (9,2), (18,1).
Both 3×6 and 2×9 are valid.
Answer: (D) Both B and C
Q 2
MCQ
If A = [aij]m×n is a square matrix, then which condition must hold?
✅ Solution
A square matrix has equal number of rows and columns.
Answer: (C) m = n
Answer: (C) m = n
Q 3
MCQ
The element a23 of a matrix A = [aij] where aij = ½|i − 3j| is:
✅ Solution
a23 = ½|2 − 3×3| = ½|2 − 9| = ½ × 7 = 7/2
Answer: (D) 7/2
Answer: (D) 7/2
Q 4
MCQ
If a matrix has 24 elements, which of the following is NOT a possible order?
✅ Solution
5 × 5 = 25 ≠ 24. All others are factor pairs of 24.
Answer: (C) 5 × 5
Answer: (C) 5 × 5
Q 5
MCQ
If A = [aij]3×3 is a diagonal matrix with a11=2, a22=−1, a33=5, what is a12?
✅ Solution
In a diagonal matrix, all non-diagonal elements are 0. Since 1 ≠ 2, a12 = 0.
Answer: (D) 0
Answer: (D) 0
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Q 6
MCQ
If A = [[2,4],[3,2]] and B = [[1,3],[−2,5]], what is the element at position (1,2) in A + B?
✅ Solution
(A+B)12 = a12 + b12 = 4 + 3 = 7
Answer: (B) 7
Answer: (B) 7
Q 7
MCQ
For two matrices A (m×n) and B (n×p), the order of the product AB is:
✅ Solution
If A is m×n and B is n×p, then AB is m×p. The inner dimensions must match.
Answer: (B) m × p
Answer: (B) m × p
Q 8
MCQ
If A = [[3,−2],[4,−2]] and I = [[1,0],[0,1]], find k so that A² = kA − 2I.
✅ Solution
A² = [[3,−2],[4,−2]]×[[3,−2],[4,−2]] = [[9−8, −6+4],[12−8, −8+4]] = [[1,−2],[4,−4]]
kA − 2I = [[3k−2, −2k],[4k, −2k−2]]
Comparing: 3k−2=1 → k=1; −2k=−2 → k=1. ✓
Answer: (A) k = 1
kA − 2I = [[3k−2, −2k],[4k, −2k−2]]
Comparing: 3k−2=1 → k=1; −2k=−2 → k=1. ✓
Answer: (A) k = 1
Q 9
MCQ
A square matrix A is skew symmetric if:
✅ Solution
By definition, A is skew symmetric if A' = −A. Diagonal elements must all be 0.
Answer: (B) A' = −A
Answer: (B) A' = −A
Q 10
MCQ
The number of all possible matrices of order 3×3 with each entry 0 or 1 is:
✅ Solution
A 3×3 matrix has 9 entries. Each can be 0 or 1 (2 choices).
Total = 2⁹ = 512
Answer: (D) 512
Total = 2⁹ = 512
Answer: (D) 512
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Q 11
MCQ
If A and B are symmetric matrices of same order, then AB − BA is a:
✅ Solution
(AB−BA)' = (AB)' − (BA)' = B'A' − A'B' = BA − AB = −(AB−BA)
So AB−BA is skew symmetric.
Answer: (B) Skew symmetric matrix
So AB−BA is skew symmetric.
Answer: (B) Skew symmetric matrix
Q 12
MCQ
If A = [[2,3],[1,2]] and B = [[2,−3],[−1,2]], then AB = ?
✅ Solution
AB = [[4−3, −6+6],[2−2, −3+4]] = [[1,0],[0,1]] = I
This means B = A⁻¹.
Answer: (A) [[1,0],[0,1]]
This means B = A⁻¹.
Answer: (A) [[1,0],[0,1]]
Q 13
MCQ
The transpose of a matrix A = [[1,2,3],[4,5,6]] has order:
✅ Solution
A is 2×3. Transpose A' swaps rows and columns, so A' is 3×2.
Answer: (B) 3 × 2
Answer: (B) 3 × 2
Q 14
MCQ
Matrices A and B are inverses of each other only if:
✅ Solution
By definition of inverse matrix: B = A⁻¹ if and only if AB = BA = I.
Answer: (D) AB = BA = I
Answer: (D) AB = BA = I
Q 15
MCQ
If A is a square matrix such that A² = A, then (I + A)³ − 7A equals:
✅ Solution
(I+A)³ = I³ + 3I²A + 3IA² + A³ = I + 3A + 3A + A (since A²=A, A³=A)
= I + 7A
So (I+A)³ − 7A = I + 7A − 7A = I
Answer: (C) I
= I + 7A
So (I+A)³ − 7A = I + 7A − 7A = I
Answer: (C) I
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Section B — Short Answer (Numerical)
Write the answer in one word / number | Each question carries 2 marks
Q 16
Short
If aij = (i + 2j)² / 2, find the element a11 of the 2×2 matrix.
✅ Solution
a11 = (1 + 2×1)² / 2 = (3)² / 2 = 9/2
Answer: 9/2
Answer: 9/2
Q 17
Short
Find x if [[4,3],[x,5]] = [[y,z],[1,5]] — specifically, what is the value of x?
✅ Solution
By equality of matrices, corresponding elements are equal.
x = 1 (comparing (2,1) elements)
Answer: x = 1
x = 1 (comparing (2,1) elements)
Answer: x = 1
Q 18
Short
If 2X + Y = [[1,0],[3,2]] and X + 2Y = [[−1,6],[0,2]], find the sum of all elements of matrix X.
✅ Solution
Subtracting 2nd from 2×(1st): 3X = 2[[1,0],[3,2]] − [[−1,6],[0,2]] = [[3,−6],[6,2]]
X = [[1, −2],[2, 2/3]]
Sum = 1 + (−2) + 2 + 2/3 = 1 + 2/3 = 5/3
Alternative: Use eqn (1)×2 − eqn (2): 3X = [[3,−6],[6,2]] → X = [[1,−2],[2,2/3]] Answer: 5/3
X = [[1, −2],[2, 2/3]]
Sum = 1 + (−2) + 2 + 2/3 = 1 + 2/3 = 5/3
Alternative: Use eqn (1)×2 − eqn (2): 3X = [[3,−6],[6,2]] → X = [[1,−2],[2,2/3]] Answer: 5/3
Q 19
Short
If A = [[1,2],[3,4]], calculate the element at position (1,1) of A².
✅ Solution
A² = A×A. The (1,1) element = (row 1 of A) · (col 1 of A) = 1×1 + 2×3 = 1 + 6 = 7
Answer: 7
Answer: 7
Q 20
Short
For matrix A = [[1,5],[6,7]], find the (2,1) element of (A − A').
✅ Solution
A' = [[1,6],[5,7]]
A − A' = [[0,−1],[1,0]]
(A−A')21 = 1. Note: A−A' is always skew-symmetric.
Answer: 1
A − A' = [[0,−1],[1,0]]
(A−A')21 = 1. Note: A−A' is always skew-symmetric.
Answer: 1
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Q 21
Short
If A = [[cosθ, sinθ],[−sinθ, cosθ]], find the value of A² at θ = π/2 — specifically element (1,2).
✅ Solution
Using A^n = [[cos(nθ), sin(nθ)],[−sin(nθ), cos(nθ)]], for n=2 and θ=π/2:
A² = [[cos π, sin π],[−sin π, cos π]] = [[−1,0],[0,−1]]
Element (1,2) = 0
Answer: 0
A² = [[cos π, sin π],[−sin π, cos π]] = [[−1,0],[0,−1]]
Element (1,2) = 0
Answer: 0
Q 22
Short
Find the value of y if [[x+y, 2],[5+z, xy]] = [[6,2],[5,8]].
✅ Solution
From (1,1): x + y = 6
From (2,2): xy = 8
So x and y are roots of t² − 6t + 8 = 0 → (t−2)(t−4) = 0
x = 2, y = 4 or x = 4, y = 2
Answer: y = 2 or y = 4
From (2,2): xy = 8
So x and y are roots of t² − 6t + 8 = 0 → (t−2)(t−4) = 0
x = 2, y = 4 or x = 4, y = 2
Answer: y = 2 or y = 4
Q 23
Short
How many elements does a matrix of order 4 × 3 have?
✅ Solution
Number of elements = m × n = 4 × 3 = 12
Answer: 12
Answer: 12
Q 24
Short
If A is a matrix such that A + A' = O (zero matrix), what type of matrix is A?
✅ Solution
A + A' = O → A' = −A → A is a skew symmetric matrix.
Answer: Skew Symmetric
Answer: Skew Symmetric
Q 25
Short
If A = [[1,0],[0,1]] (Identity matrix I₂) and B = [[3,0],[0,4]], find the element (2,2) of AB.
✅ Solution
Since A = I, AI = IA = A for any matrix. So AB = B = [[3,0],[0,4]].
Element (2,2) = 4
Answer: 4
Element (2,2) = 4
Answer: 4
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